December 25, 2009
I can hold a lot
PlayIf 1 = 2/3, identify 1,2 and 3.
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Answer:
Farad = Coulomb / Volt
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1.Michael Faraday
2.Coulomb
3.Volta
Farad = Coulomb / Volt
faraday coulomb and volta
1 C = 1 F * 1 V
C=Q/V
faraday=coulomb/volta
Michael Faraday, Charles Coulomb and Alessandro Volta respectively. F = C/V.
faraday coulomb volta – wasn\’t a similar question been asked before
C=Q/V
1. Michael Faraday 2. Charles-Augustin de Coulomb 3. Alessandro Volta
1 farad= coulomb/volt
2 – de Coulomb.
1 – Michael Faraday.
therefore,
3 – Alessandro Volta.
And from wiki :
A farad is the charge in coulombs a capacitor will accept for the potential across it to change 1 volt.
1>Michael Faraday
2>Christopher Columbus
3>Alessandro Volta
Farad = Coulomb / Volt. Hence Farad, Coulomb, Volta.
farad = coulomb/volt
1 = Michael Faraday
2 = Charles Augustin de Coulomb
3 = Alessandro Volta
But…
One coulomb is the amount of charge stored by a capacitance of one farad charged to a potential difference of one volt:
1C = 1F x 1V
So, my laws aren\’t matching up with the formula as given.
Heh. Never heard of a coulomb/volt before. I read now that 1 farad = 1 coulomb/volt. Or, more precisely 1 farad = 1.00049024022 coulomb/volt.
faraday, coulomb and volta
C = Q/V
Michael Faraday
Coulomb
Volta
Faraday, Coulomb, Volta.
The SI unit of capacitance is Farad.
1. Farady
2. Coulomb
3. Volta
Farad = Coulomb / Volt.
Phew.
A farad is the charge in coulombs a capacitor will accept for the potential across it to change 1 volt. A coulomb is 1 ampere second.
1. Michael Faraday
2. Charles-Augustin de Coulomb
3. Alessandro Volta
Faraday, Coulomb & Volta