December 8, 2013
Did I seriously miss adding a title?
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2013-12-15 This is a sprinkler connected to a pump. When the pump is pressed (the rubber sphere in the end), the sprinker rotates. As expected.
What happens when the pump is released? What is this problem called as?
BTW, this is one of the most debated topics among internet noobs and all.
Cracked by: Dibyo , Sumanth Patlolla , s m muneer ali , Manish Achuth and Rogi
Answer:
Feynman’s reverse sprinkler. The sprinkler will not rotate in the opposite direction, but if you place it in an idea fluid and replace all the ball bearings in the sprinkler with ideal bearings, it will rotate in the opposite direction. I think :)
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Feynman sprinkler, or reverse-sprinkler?
Feynman sprinkler
When the rubber ball is released, the direction of the flow of the air is reversed but Ernst Mach observed “no distinct rotation” of the device.
Feynman Reversible Spinkler.
If it’s sitting in air, nothing will happen.
If it’s sitting in a perfect viscous fluid and had perfect bearings, it would go backwards as the friction of the fluid in the tubes is overcome by Newtonian forces. This contradicts Feynman’s assertions as it has been proven to go in the reverse direction in most college physics labs. using a rig that looks a lot like a Hero engine placed on its side.
Feynman Sprinkler. Reverse sprinkler problem.
So… I can only assume that nobody’s said the right thing, yet since the question isn’t showing moderation and the title was updated.
To that end…
Feynman sprinkler